Question

the function of h is defined by h(x)=(20x-k)/(x)+50 where k is a constant. find k if the value of h at x=20 is equal to 65

Answer 1

substitute in the function and solve for k

65=\frac{20(20)-k}{20}+5065= 20

l20(20)−k +50

65-50=\frac{400-k}{20}65−50= 20

400−k

15=\frac{400-k}{20}15= 20

400−k

15*20=400-k15∗20=400−k

300=400-k300=400−k

k=400-300=100k=400−300=100

Answer 2

Answer:

h(x) = (20x-k) /(x) + 50

according to condition,

65 = (20×20-k) /(20) +50

(65-50)×20 = (400-k)

15×20 = 400-k

so, k = 100 answer