The function Sin (x^{2} )+cos(x^{0.5})is periodic with period βπ. Then β =
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Answer:
Explanation:
f
(
x
)
=
y
=
0.5
sin
x
cos
x
y
=
(
1
2
)
2
sin
x
cos
x
2
y
=
(
1
4
)
sin
2
x
It’s in the form
y
=
a
sin
(
b
x
+
c
)
+
d
where,
a
=
1
4
,
b
=
2
,
c
=
d
=
0
Amplitude
=
a
=
(
1
4
)
Period
=
2
π
|
b
|
=
2
π
2
=
π
graph{0.5 (sin (x) cos (x)) [-10, 10, -5, 5]}
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