Question

The function 't' which maps temperature in Celsius (C) into temperature in Fahrenheit (F) is defined by t(C) = F where F = 9/5C+32.find,
(i) t(0)
(ii) t(28)
(iii) t(-10)
(iv) the value of C when t(C) = 212
(v) the temperature when the Celsius value is equal to the Farenheit value.​

Answer 1

Answer:

i) +32

ii) +412/5

iii) +14

iv) 100

Step-by-step explanation:

Given

t(C) = 9/5C + 32

• putting C = 0

t(0) = 9/5×0 + 32

0 + 32

= +32

• putting C = 28

t(28) = 9/5 × 28 + 32

252/5 + 32

= 412/5

• putting C = -10

t(-10) = 9/5 × -10 + 32

-90/5 + 32

= -18 + 32

= + 14

•putting the(C) = 212

212 = 9/5 C + 32

9/5 C = 212-32

C = 180×5/9

C = 100