The function 't' which maps temperature in degree Celsius into temperature in degree Fahrenheit is defined by
Find t(0)
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f (Fahrenheit) = 9/5*C + 32
Which means, at Celsius = 0° C
Fahrenheit = 9/5(0)+32 = 32 F.
Which means, at Celsius = 0° C
Fahrenheit = 9/5(0)+32 = 32 F.
Anonymous:
nice answer bro
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The function t which maps temperature I. degree Celsius into temperature in degree Farhenhiet is defined by

here, t(C) denotes farhenhiet and C denotes Celsius.
you should under that , C is independent variables and t(C) is dependent variable because value of t(C) depends on C.
so, we can say that. value of C is domain and value of t(C) is range of the given function.
now come to the question,
we have to find t(0)
here 0 in place of C .
hence, we have to put C = 0 in the given function
so, t(0) = 9 × 0/5 + 32 = 0 + 32 = 32°F
here, t(C) denotes farhenhiet and C denotes Celsius.
you should under that , C is independent variables and t(C) is dependent variable because value of t(C) depends on C.
so, we can say that. value of C is domain and value of t(C) is range of the given function.
now come to the question,
we have to find t(0)
here 0 in place of C .
hence, we have to put C = 0 in the given function
so, t(0) = 9 × 0/5 + 32 = 0 + 32 = 32°F
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