the function x^3 +xcosx + sinx +1 is odd function or even function
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Ravinderjit:
how to identify neither odd neither even function
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put
f(-x) = (-x)³ +(-x)cos(-x) + sin(-x) +1
= -x³ - xcosx - sinx +1
= - (x³ +xcosx+sinx -1 )
≠ -f(x) ≠ f(x)
so function is not odd or even
f(-x) = (-x)³ +(-x)cos(-x) + sin(-x) +1
= -x³ - xcosx - sinx +1
= - (x³ +xcosx+sinx -1 )
≠ -f(x) ≠ f(x)
so function is not odd or even
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