Physics, asked by tariqrahim944, 4 months ago


The fundamental frequency of a closed organ pipe is f. If both the
ends are opened then its fundamental frequency will be
a. f
b. 0.5f
c. 21 d. 41​

Answers

Answered by hardeepdaroch2
2

Answer:

a

Explanation:

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Answered by RitaNarine
0

If both the ends are opened then its fundamental frequency will be 0.5f

option B is the correct answer.

Given:

Frequency of a closed organ pipe (f_{c} )= f

To find:

organ pipe's fundamental frequency if both the

ends are opened.

Solution:

first of all, we have to know what is an organ pipe.

  • An Organ pipe is a sound-producing device that resonates at a specific pitch.
  • A closed organ pipe is one in which one end of an organ pipe is closed and the other end is open.
  • When both ends of an organ pipe are open, it is referred to as an open organ pipe.

An open organ pipe's fundamental frequency (f_{o} )= \frac{v}{2l}

Frequency of the closed organ pipe (f_{c} ) = \frac{nv}{4l}

Where n = positive integer,

v = velocity of sound,

and l = length of the organ pipe.

An open organ pipe's fundamental frequency (f_{o} )= \frac{v}{2l} = 2f_{c}

hence, f_{c} = \frac{f_{o}}{2}

f_{c} = \frac{f}{2}

=0.5 f\\

hence, option (B) 0.5f is the correct answer.

If both the ends are opened then its fundamental frequency will be 0.5f

#SPJ2

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