Question

The fundamental frequency of a closed organ pipe of length 20 cm is equal to the second overtone of an organ pipe open at both the ends. The length of organ pipe open at both the ends is

Answer 1

Answer:

$fundamental \: freq \: of \: ccp = sec \: overtone \: of \: oop \\ \frac{v}{4lc} = \frac{3v}{2lo} \\ \frac{1}{20 \times 2} = \frac{3}{lo} \\ lo \: = 120$

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