The fundamental frequency of vibration of a streached string of length 1m is 256HZ.Find the frequency of the Same string of half the original length under identical condition
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Answer:
fundamental frequency of vibration of a streached string of length 1m is 256HZ.Find the frequency of the Same string
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Explanation:
frequency =
2lν =256×2×1=νNow taking same ν
f= 2lν= 2×0.64
256×2×1
(since length is decreased by 0.36m here length is 1−0.36=0.64m)
=400 Hz.
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