Question

The gas A2 in the left flask allowed to react with gas B2 present in right flask as
A2(g)+B2(g) ? 2AB(g); Kc=4 at 27°C.
What is the concentration of AB when equilibrium is established?

Answer 1

Hey bae,

● Answer-
[AB] = 2√(xy)

● Explaination-
# Given-
Kc = 4
# Solution-
Here, the reaction occurs as follows
A2 + B2 ---> 2AB

When equilibrium is established, equilibrium constant is given by-
Kc = [AB]^2 / [A2][B2]
[AB]^2 = Kc [A2][B2]

Let x = [A2] y = [B2]
[AB]^2 = 4x.y
[AB] = 2√(xy)

Hope this is helpful...

Answer 2

hope this will help you.........