Question

The gas has a volume of 2.7 ml. What is the initial pressure if volume
becomes 5.8L at 2.atm?​

Answer 1

l

Explanation:

P1V1=P2V2

P1 × 2.7 ml = 5.8 L × 2 ATM

P1 = (5.8 L ×2atm) ÷ 2.7 ml

= 4.29atm