The gas has a volume of 2.7 ml. What is the initial pressure if volume
becomes 5.8L at 2.atm?
Answers
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l
Explanation:
P1V1=P2V2
P1 × 2.7 ml = 5.8 L × 2 ATM
P1 = (5.8 L ×2atm) ÷ 2.7 ml
= 4.29atm
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