Question

The gas in a closed container has a pressure of 2.96 atm at with a volume of 3L. What would the pressure be if the volume is reduced to 2L

Answer 1

Answer:

Explanation:

pv=a constant

P(initial)V(initial)=P(final)V(final)

∴   2.96×3=P×2

p=(2.96×3)/2=4.44