Question

the gas in a vessel is subjected to preserve 20 atmosphere at and temperature 27 degree Celsius the pressure of the gas in the vessel after one half of the gas is released from The vessel and the temperature of the remainder is raised by 50 degrees is

Answer 1

The pressure in the vessel will be 11.66 atmosphere.

From the gas law we know that,

PV = nRT

since volume and R are constant

=> P/nT = constant

=> P₂/n₂T₂ = P₁/n₁T₁

=> P₂ = P₁n₂T₂/n₁T₁

if Initial number of moles = 1 => final number of moles = 0.5

T₁ = 27°C = 273 + 27 = 300 k

T₂ = 300 + 50 = 350 k

P₁ = 20

putting the above values in the equation we get,

P₂ = 20 x 0.5 x 350/( 1 x 300)

= 3500/300

= 11.66 atm

Hence the pressure in the vessel will be 11.66 atmosphere.