Question

The gas which has the density of 5.33g/l at
8. 2 latmpressure & 27c is.​

Answer 1

Answer:

n2

CO2

O2

ch4

Explanation:

it is a better answer

Answer 2

The gas is Oxygen

Explanation:

Given:

A gas has

Density ρ = 5.33 g/Lt

Pressure P = 8.2 atm

Temperature T=27 °C

To find out:

What gas it is

Solution:

We know that the gas equation in their usual notations is

$PV=nRT$

If mass of the gas is m and molar mass M

Then

$P\frac{m}{\rho}=\frac{m}{M}RT$

$\implies \frac{P}{\rho}=\frac{RT}{M}$

$\implies M=\frac{RT\rho}{P}$

$\implies M=\frac{0.08206\times (273+27)\times 5.33}{8.2}$

$\implies M=16$

Therefore, the gas is Oxygen (O₂)

Hope this answer is helpful

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