The GCD of 12 , 1s 5 and 7 a) 12 b) 3 c) 15 d) 1 2) log 15 -log = log x, then x= a)5 y6 b) 5 by 3 c) 8 by 5 d) 6 by 5 3) log x =m a) a power m b) x power m c) X into a into m d) m by a
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Step-by-step explanation:
(i) {(2,1),(5,1),(8,1),(11,1),(14,1),(17,1)}
It is a function as every input has a single output.
So, 2,5,8,11,14 and 17 are the elements of the domain of the given relation.
Here domain ={2,5,8,11,14,17} and range ={1}
(ii) {(2,1),(4,2),(6,3),(8,4),(10,5)(12,6),(14,7)}
It is a function as every input has a single output.
So, 2,4,6,8,10,12 and 14 are the elements of the domain of the given
relation.
Here domain ={2,4,6,8,10,12,14} and range ={1,2,3,4,5,6,7}
(iii) {(1,3),(1,5),(2,5)}
Since the element 1 corresponds to two different images i.e., 3 and 5 . So, this relation is not a function.
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