Math, asked by venkannathati, 2 months ago

The GCD of 4a2b2 & 20ab2 is​

Answers

Answered by Anweshapaik
0

Answer:

Factors of 4a2b2=4×a×a×b×b

Factors of 20ab2=4×5×a×b×b

GCD is the greatest common divisor, which is equal to the product of all the common divisors.

∴ The GCD of 4a2b2, 20ab2 is 4ab2

Similar questions