Math, asked by arundhawann650, 17 days ago

THE GCD OF a^3 + 2a^2 – 3a and 2a^3 + 5a^2 – 3a​

Answers

Answered by ajaydhayal
2

Answer:

LCM(x,y)=HCF(x,y)x×y

∴LCM=(a2+5a+7)(a4+3a3+5a2+26a+56)×(a4+2a3−4a2−a+28)

LCM=(a2+5a+7)(a2+5a+7)(a2−2a+8)(a4+2a3+4a2−a+28)=(a2−2a+8)(a4+2a3−4a2−a+28) 

Step-by-step explanation:

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Answered by mahanteshgejji
1

Answer:

The GCD is[ a^2-a]

Step-by-step explanation:

The factors of a^3+2a^2-3a are

a[a^2+2a-3]

=a(a+3)(a-1)

The factors of 2a^3+5a^2-3a are

=a[2a^2+5a-3]

=a(a+6) (a-1)

GCD = a(a-1) = a^2-a

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