The general electronic configuration of Lanthanide atoms is (A) Xe] 6S25d14fn (B) [Xe] 6s24d4f" (C) (Xe] 6S24f" (D) Xe 7s25d14f
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Answer:
\[\left( {n - 2} \right){f^{1 - 14}}\left( {n - 1} \right){d^{0 - 1}}n{s^2}\]
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