Question

The general solution of 2cos2α-√3=0

Answer 1

Answer:

Step-by-step explanation:

2cos2α-√3 = 0

Cos2α=√3/2

Cos2α=cos 30°

2α=30°

α=15°

Answer 2

Answer:

$a=\frac{\pi }{12} +\pi n\\a=\frac{11\pi }{12} +\pi n$

Step-by-step explanation:

Given,

$2cos2\alpha -\sqrt{3} =0$

        $2cos2\alpha =\sqrt{3}$

               $2a=\frac{\pi }{6} +2\pi n\\2a=-\frac{\pi }{6} +2\pi n$

                 $a=\frac{\pi }{12} +\pi n\\a=\frac{11\pi }{12} +\pi n$