Question

The general solution of sin = 0 is

(a) nπ where n is a real number

(b) nπ, where n is an integer

(c) 2π

(d) π

Answer 1

$\implies$

• we know that if sin x = 0, then x = 0, π, 2π, π, -2π, -6π, etc.
• are solutions of the given equation.
• Hence, the general solution for sin x = 0 will be, x = nπ, where n∈I.

Answer 2

Q) The general solution of sin = 0 is

(a) nπ where n is a real number

(b) nπ, where n is an integer

(c) 2π

(d) π

ANSWER:-

Option - A - nπ where n is a real number