Question

the general solution of sinx- 3 sin2x + sin3x = cosx - 3cos2x + cos3x​

Answer 1

Answer:

using C-D formulae :

we get

2sin2xcosx−3sin2x=2cos2xcosx−3cos2x

(2cosx−3)sin2x=(2cosx−3)cos2x

cos2x=sin2x

tan2x=1

x=2nΠ+8Π

Answer 2

Answer:

using C-D formulae :

we get

2sin2xcosx−3sin2x=2cos2xcosx−3cos2x

(2cosx−3)sin2x=(2cosx−3)cos2x

cos2x=sin2x

tan2x=1

x=2nΠ+8Π