Question

The general solution of the equation (D-moD')²z = 0 is​

Answer 1

Answer:

Explanation:

1+x  

2

 

2x

​

dx=  

1+y  

2

 

−2y

​

dy

⇒ log(1+x  

2

)=−log(1+y  

2

)+logk

⇒ (1+x  

2

)(1+y  

2

)=k