Question

The general solutions of sin θ + sin 2θ + sin 3θ = 0 is

Answer 1

Answer:

Step-by-step explanation:

(sinθ+sin3θ)+(sin2θ+sin4θ)=0

2sin2θcosθ+2sin3θcosθ=0

2cosθ(sin2θ+sin3θ)=0

4cosθsin(5θ/2)cos(θ/2)=0

cosθ=0=cos(π/2),

∴θ=(n+  

2

1

​  

)π

cos(θ/2)=0=cos(π/2),

∴  

2

θ

​  

=(n+  

2

1

​  

)π or θ=(2n+1)π

sin(5θ/2)=0=sin0

∴(5θ/2)=nπ or θ=2nπ/5.

Answer 2

Step-by-step explanation:

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