Question

the general term of the sequence is given by an=-4n+15.is the sequence forming an ap ​

Answer 1

Answer:

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Step-by-step explanation:

an=-4n+15

a(n+1)=-4(n+1)+15

a(n+1)=-4n+11

now we have to take the difference betn them because we know that "In an ap common difference is same" ok?

so, a(n+1)-an=-4 which is a constant value, so it is an ap

Got it?

Thanks a lot

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