The generalised form of 199 is:
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Generalised for 199 = (2*100) - 1
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Step-by-step explanation:
By numbers, I've assuming you're referring to natural numbers.
This is an arithmetic progression, with a common difference d=1 . The first term a=1 and the last term an=199 .
an=a+(n−1)d=n
⇒n=199
Therefore, there are 199 terms. Now,
S=n2⋅(a+an)=12⋅199⋅200=100⋅199=19900 .
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