Question

. The genetic distance between genes A and B is 10 cm. An organism with Ab combination of the alleles is crossed with the organism with aB combination of alleles. What will be the percentage of the gametes with AB allele combination by an F1 individual ?​

Answer 1

Percentage of the gametes:

This is a problem with the law of independent assortment.  

The genetic combination of first parent = Ab

The genetic combination of the second parent = aB

So, all the probable gametes $=A b \times a B$

= AB, Ab, aB, ab.  

So, the percentage of the population with combination A $B=\frac{1}{4}=25 \%$

The individual with gamete having combination AB will have to have both the AB genes present in it.  

So, only AB individuals will be able to produce AB gametes.