Chemistry, asked by karthya4756, 1 year ago

The geometries of the ammonia complexes of Ni²⁺, Pt²⁺ and Zn²⁺ respectively, are (a) octahedral, square planar and tetrahedral(b) square planar, octahedral and tetrahedral(c) tetrahedral, square planar and octahedral(d) octahedral, tetrahedral and square planar

Answers

Answered by Anonymous
1

no clue soryy i hope you can find the answer

Answered by rg598555
0

Answer:

(a) octa, s.p, tetra

Explanation:

1.) Ni - nickel lies in last of the spectroscopy series of metals (ya metals).

so it has low splitting, you can see, ammonia do not split d orbitals of Ni.

so it can have sp3 or sp3d2 only. to be stable it forms sp3d2 because Δo is greater than Δt

2.) Pt - pt is down the grp of ni. it have more splitting tendency, so ammonia splits d orbitals and electrons get paired. so it have one d empty.

it forms dsp2 . Δsp>Δo>Δt.

3.) zn - too easy , it has d10 so, it can have only sp3 or sp3d2.

it forms sp3 because having s, px, py, pz  filled it will attain noble gas config.

concepts used-

Δsp>Δo>Δt

Δ increases down the group

coordination entity attain or try to attain nearest noble gas config.

Similar questions