The gibbs energy for the decomposition of Al2O3 at 500 0 C is +960kJ/mol .the pot. difference needed for electrolytic reduction of Al2O3 is?
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ΔG = - n F Ε°
n = 4 for Aluminum decomposition in to Al and O2. 4 moles of electrons are transferred. F = Faraday = 96500 Coul/mole
E° = - ΔG / n F = - 960 * 1000 /(4 * 96500) = - 2.48 V
n = 4 for Aluminum decomposition in to Al and O2. 4 moles of electrons are transferred. F = Faraday = 96500 Coul/mole
E° = - ΔG / n F = - 960 * 1000 /(4 * 96500) = - 2.48 V
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