the given carbon containing compound have 50 2.17 % of carbon and 104%of hydrogen and rest being oxygen its molar mass equal to 46 gram per mole find its empirical formula and molecular formula
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Explanation:
Percentage of O is 34.76
C:H:O = 52.20/12 : 13.04/1 : 34.76/16 = 4.33 :--
13:12:15 = 2:6:1
Equivalent weight = 46
Molecular weight = 2 × 23 = 46
x= 46/46 = 1
molecular formula = (empirical formula) x
molecular formula = C2H6O
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