The given carbon containing compound having 50%of carbon and 104% of hydrogen and rest being oxygen. its molar mass = 46 g/mole . find is empirical formula and molecular formula.
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Explanation:
Element Atomic Mass Relative no. of atoms Simplest Ratio Whole no. Ratio
C (50%) 12 4.166 1.33 1.33×3=4
O (50%) 16 3.125 1 1×3=3
∴ Empirical formula= C
4
O
3
Mass= (4×12)+(3×16)=96
n=
Empirical mass
Molecular mass
=
96
288
=3
∴ Molecular formula= n× Empirical formula
=3(C
4
O
3
)
=C
12
O
9
.
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