Question

The given carbon containing compound having 50%of carbon and 104% of hydrogen and rest being oxygen. its molar mass = 46 g/mole . find is empirical formula and molecular formula.
​

Answer 1

Answer:

Atomic Mass Relative no. of atoms Simplest Ratio Whole no. Ratio

C (50%) 12 4.166 1.33 1.33×3=4

O (50%) 16 3.125 1 1×3=3

∴ Empirical formula= C

4

O

3

Mass= (4×12)+(3×16)=96

n=

Empirical mass

Molecular mass

=

96

288

=3

∴ Molecular formula= n× Empirical formula

=3(C

4

O

3

)

=C

12

O

9

.

Answer 2

Answer:

Oᖇ ᗰᗴᖇᗴ ᗰᗩᑕᕼII KᗴՏᗴ ᕼᗩI Տᗩᗩᗷ TIK ᑎᗩᗩ

Element Atomic Mass Relative no. of atoms Simplest Ratio Whole no. Ratio C (50%) 12 4.166 1.33 1.33×3=4 O (50%) 16 3.125 1 1×3=3 ∴ Empirical formula= C4 O3 Mass= (4×12)+(3×16)=96n= Empirical massMolecular mmas = 288/96 =3∴ Molecular formula= n× Empirical formula =3(C4 O3 ) =C12 O9 .

ᕼOᑭᗴ ITՏ ᕼᗴᒪᑭᖴᑌᒪ TO YOᑌ