The given diagram shows a series of images of a moving ball captured by a camera.
The ball was moving at a constant speed and the images were taken at a constant rate of 10 per second. What is the speed of the ball?
(1) 30 ms–1
(2) 20 ms–1
(3) 45 ms–1
(4) 15 ms–1
Answers
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Given .. (1) time taken to take 10 shots=1 sec ==> time taken to take one shot= 1/10 sec (2) Distance travelled by ball while camera took 6 shots =15 meter We know , speed= distance/time Distance=15m Time= Not known... lets find out the time to take six shots Fist shot was taken after = 0sec (as first short was taken at beginning) Second shot taken after = 1*(1/10) = 1/10 seconds Third short taken after = 2*(1/10) =2/10 seconds Similarly .. sixth shot taken after = 5*(1/10) =5/10 Now.. speed = distance/time = 15 / (5/10) = 30 m/second
Hope, it helps.
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Answer:
1. 30 ms–1
Explanation:
Given that it takes one second to shoot ten shots, one shot would take one-tenth of a second to take.
Ball travelled 15 metres while the camera took 6 pictures.
Knowing that speed equals distance/time Distance=15m Time= Unknown, let's determine the timing for six shots. After = 0 seconds, the fist shot was fired (as first short was taken at beginning)
The following picture was taken after = 1*(1/10) = 1/10 seconds.
Taking a third short after is equal to 2*(1/10) = 2/10 seconds.
Similar to that, the sixth shot after equals 5*(1/10) = 5/10.
Now, speed is calculated as follows: 15 / (5/10) = 30 m/s
Speed is determined by dividing the distance travelled by the time taken to travel it. It gives the amount of time it took to travel a certain distance divided by the distance travelled.
Speed is inversely correlated with time and directly correlated with distance. As a result, distance equals speed times time, and time equals distance divided by speed; as speed rises, distance travelled will shorten, and vice versa.
These equations can be used to solve any simple problems. But when using formulas, it's also crucial to remember to use the right units.
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