Math, asked by ParthDudani11, 9 months ago

the given expression wherever defined simplifies to​

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Answered by BrainlyPopularman
1

Answer:

 { \bold{=  \frac{ \cot( \alpha )( -  \sin( \alpha ))  }{ \cos( \alpha )  } +  \sin( \alpha )  \sin( \alpha )  + ( -  \cos( \alpha )   )( -  \cos( \alpha )) }} \\  \\   { \bold{ = -  \frac{ \frac{ \cos( \alpha ) }{ \sin( \alpha )  }  \times  \sin( \alpha ) }{ \cos( \alpha ) }  }} +  {sin}^{2} ( \alpha ) +  {cos}^{2} ( \alpha ) \\  \\  =  - 1 + 1 \\  \\  = 0 \\  \\  \\  \\ { \bold{ \boxed{ \green{ \huge{FOLLOW ME ...}}}}}

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