Question

the given figure AB=AC and angle A = 50 degree find the value of angle BCF. Single choice.
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Answer 1

Step-by-step explanation:

let G be the point where F intersects E

so, now in quadrilateral AFEG

we have

A+F+E+G= 360

50+90+90+G= 360

G= 360-230= 130

Here G is the angle FGE or BGC as vertical angles

as we know that two sides are equal we can confirm that the triangle is isosceles∆

in ∆BCG,

B=C

C+C+G= 180

2C+130= 180

2C= 180-130

C= 50/2 = 25

therefore angle BCF= 25°