Question

the given figure ab=bc and ac=cd if angle bad=y and angle adb=x then angle y=​

Answer 1

Answer:

Step-by-step explanation:Let ∠ADB=x

In △ACD,AC=CD

⇒∠CAD=∠CDA=x

and, ∠ACB=∠CAD+∠CDA=x+x=2x

⇒∠BAC=∠ACB=2x.(∵ In ABC,AB=BC)

∴∠BAD=∠BAC+∠CAD

=2x+x=3x

And,  

∠ADB

∠BAD

​

=

x

3x

​

=

1

3

​

i.e., ∠BAD:∠ADB=3:1 [henceproved]

Pls mark me as the brainliest