Question

the given figure, AB= BC and LABD= ZCBD. Prove that _DAB = ADCB.
A
B
D​

Answer 1

Answer:

(a) AB = DC (given)

∠ABC = ∠DCB (given)

BC = BC (common)

Therefore ΔABC congruent to ΔDBC (SAS congruence)

(b) ∠A = ∠D (CPCT)

(c) ∠AOB = ∠DOC

∠A = ∠D

AB = DC

Therefore ΔAOB congruent to ΔDOC (AAS congruence)

(d) OB = OC (CPCT)

Therefore, ΔBOC is isosceles.