Question

the given figure AD is the diameter of the circle
with centre 0, find the values of x and y.
50
B
A А​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

It is given that O is the centre of the circle and ∠DAB = 50o We know that the radii of the circle are equal OA = OB From the figure we know that ∠OBA = ∠OAB = 50o Consider △ OAB Using the angle sum property ∠OAB + ∠OBA + ∠AOB = 180o By substituting the values 50o + 50o + ∠AOB = 180o On further calculation ∠AOB = 180o – 50o – 50o By subtraction ∠AOB = 180o – 100o So we get ∠AOB = 80o From the figure we know that AOD is a straight line It can be written as x = 180o – ∠AOB By substituting the values x = 180o – 80o By subtraction x = 100o We know that the opposite angles of a cyclic quadrilateral are supplementary So we get ∠DAB + ∠BCD = 180o By substituting the values 50o + ∠BCD = 180o On further calculation ∠BCD = 180o – 50o By subtraction y = ∠BCD = 130o Therefore, the value of x is 100o and y is 130oin-the-given-figure-o-is-the-centre-of-the-circle-and-dab-50-calculate-the-values-of-x-and-y

Step-by-step explanation:

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