Question

the given figure, AP = BQ, PR = QS. Show that ΔAPS = ΔBQR ​

Answer 1

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In △APS and △BQR

AP=BQ (Given)

PR=QS (Given)

∴△APS≅△BQR(S.S.S. congruency)

⇒∠APS=∠BRQ(C.P.C.T.C.)

⇒∠ASP=∠BQR (C.P.C.T.C.)

Thus, AB is bisector of ∠APS and ∠BQR

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