The given figure,BO and CO are the bisectors of angle B and angle C respectively. If angle A = 50⁰ then find angle BOC.
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a+b+c= 180
50+b+c= 180
b+c= 130(1)
divide equation (1) by 2
now in triangle obc o+1/2(b+c) = 180
1/2(b+c) = 65(2) o+65= 180 (from (2)) o= 180-65= 115
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