Question

The given figure contains two semicircular shapes
with same centre. Find the perimeter of the figure
12 cm
24 cm​

Answer 1

Answer:

68.52cm

Step-by-step explanation:

Perimeter of a circle = 2πr

radius of outer semicircle = $\frac{24}{2}=12cm$

radius of inner semicircle = $\frac{12}{2} = 6cm$

Since, perimeter of a circle is 2πr then of a semicircle is $\frac{2piR}{2}$ = πr

So, outer semicircle = πr =3.14×12 = 37.68cm

      inner semicircle = πr = 3.14×6 = 18.84cm

And 24-12 = 12cm

∴ Total perimeter is 37.68+18.84+12 = 68.52cm