the given figure, find the measures of @OCD and @BDC.
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In ∆CBD
@BCD is right angle ( 90° )
and
@ACB + @OCD = @BCD
60° + @OCD = 90°
@OCD = 90 - 60
@OCD = 30°
NOW IN ∆BCD
@DBC + @ BCD + @BCD = 180°. ( Angle sum property )
45 + 90 + @BDC = 180
@BDC = 180 - 135
@BDC = 45°
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