The given figure is a combined solid made up of a cylinder and a
cone. The radius of the base of the solid object is 7cm, length of
the cylindrical part is 35 cm, and the total length of the solid
object is 59cm. Find the total surface area of the solid object
(Ans: 2244cm)
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Answers
Answer:
Height of core =12.8−6.5−3.5=2.8 cm
Volume =Volume of cone + Volume of Cylinder +Volume of a hemisphere
=
3
1
×
7
22
×(r)
2
×h+
7
22
×(r)
2
×h+
3
2
×
7
22
×(r)
3
=
3
1
×
7
22
×(3.5)
2
×2.8+
7
22
×(3.5)
2
×6.5+
3
2
×
7
22
×(3.5)
3
=35.93+250.25+89.83
=376.01 cm
3
Explanation:
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Answer:
Height (h) of cylindrical part = height (h) of the conical part =7 cm
Diameter of the cylindrical part =12 cm
Therefore, Radius (r) of the cylindrical part =
2
12
=6 cm
So, Radius of the conical part =6 cm
Slant height (l) of conical part =
r
2
+h
2
cm
=
6
2
+7
2
=
36+49
=
85
≈9.22 cm.
The total surface area of the remaining solid = CSA of the cylindrical part + CSA of the conical part + Base area of the circular part
=2πrh+πrl+πr
2
=2×
7
22
×6×7+
7
22
×6×9.22+
7
22
×6×6
=264+173.86+113.14
=551 cm
2
Explanation:
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