Question

the given figure is made up of 10 squares of the same size the perimeter of the figure is 80 cm find the area of the figure​

Answer 1

Answer:

perimeter of 10square = 80cm

perimeter of 1 square=80/10=8

side of one square=

perimeter of square=4×s

8. =4×s

8/4= side

2cm is the side of one square

area of square =s×s

2×2

4cm²

area of 10 square=4×10

40cm

the area of figure is 40cm²

Answer 2

Given:

• The perimeter of the squares is 80 cm.
• There are a total of 10 squares of the same size.

To Find:

• The area of the 10 squares.

Solution:

• We know that perimeter = The sum of all the boundary lines of the squares.
• Let x be the length of one side of the square, there are 16 boundary lines in the figure,
• So, perimeter = 16x
• ⇒16x = 80
• ⇒x = 80/16
• ⇒x = 5 cm
• So the length of each side of a square = 5 cm.
• We know that the area of a square = side*side = 5*5
• Area = 25 $cm^2$
• For 10 such squares,
• Area of 10 squares = 25*10 = 250 $cm^2$ .

∴ The area of 10squares = 250 $cm^2$ .