Question

The given figure (not drawn to scale) is a square.
NJ = 20 cm. LM = 4 cm and PJ = 16 cm. Find the
area of the shaded region.​

Answer 1

Given :-

• NJCA is a square with each side as 20 cm.
• NP = 4 cm.
• PJ = 16 cm.

To Find :-

• Area of the shaded region ?

Solution :-

Construction :-

• Join PB .

So,

• Rectangle NPBA is same as Rectangle PJCB .

then,

→ shaded area = (Area of Rectangle NPBA / 4) + (Area of Rectangle PJCB / 4)

→ shaded area = (4 * 20 / 4) + (16 * 20 / 4)

→ shaded area = 20 + 80

→ shaded area = 100 cm². (Ans.)

Learn more :-

In ABC, AD is angle bisector,

angle BAC = 111 and AB+BD=AC find the value of angle ACB=?

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