Question

the given figure, OEB = 75°, OBE = 55° and OCD = 100°. Then ODC = ?
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Answer 1

Answer:

HI BUDDY

Step-by-step explanation:

In the angle BEO ,

angle BEO= 75°

angle OBE = 55°

By using ASP ( Angle Sum Property ) ,

angle (BEO + OBE + BOE )= 180°

angle (130° + BOE) = 180°

angle BOE = 180°-130° = 50°

angle BOE = angle COD ( not call of duty)(vertically opposite angles)

50° = angle COD

angle (COD + ODC + OCD ) = 180° (by ASP)

angle ODC = 180°- 150° = 30°

MARK THIS AS BRAINLIEST PLZ

Answer 2

Given :- In the given figure, ∠OAB is equal to 75°, ∠OBA is equal to 55° and ∠OCD is equal to 100°. Then ∠ODC is equal to ?

Solution :-

In ∆OAB, we have,

→ ∠OAB + ∠OBA + ∠AOB = 180° (By Angle sum Property.) → 75° + 55°+ ∠AOB = 180°

→ 130° + ∠AOB = 180°

→ ∠AOB = 180° - 130°

→ ∠AOB = 50°

now, as we can see that,

→ ∠COD = ∠AOB = 50° (vertically opposite Angles.)

In ∆OCD, we have,

→ ∠COD + ∠OCD + ∠ODC = 180° (By Angle sum Property.)

→ 50° + 100° + ∠ODC = 180°

→ 150° + ∠ODC = 180°

→ ∠ODC = 180° - 150°

→ ∠ODC = 30° (Ans.)

Learn more :-

In ABC, AD is angle bisector,

angle BAC = 111 and AB+BD=AC find the value of angle ACB=?

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