Question

the given figure p is a point in the interior of <AOB,PA AO and PB BO
if <AOB=35° find the measure of <APB​

Answer 1

We know: angle(P) + angle(A) +angle(O) + angle(B) = 360° [angle sum property of a quadrilateral]

So , angle(P) + 90° + 35° + 90° = 360°

So , angle(P) = 360° - (90° + 35° + 90°)

So , angle(P) = 360° - 215° = 145° {answer !!!!}

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