The given figure, PQ is diameter of the semicircle PABQ and O is its centre . angle AOB = 64° . BP cuts AQ at X , what is the value of angle AX B?
Attachments:
Answers
Answered by
4
AXB = 360 - 64 = 296
= 296/2 = 148
According to the circle theorem that the angle at the center is double the angle at the circumference.
finally:
ok
I got it but it's kind of long winded
ok
solutions mil gaya he ek daam short he batau
humm?
ohh
mera to thoda long hai
try karne li liye dhanye waad
dil se
It's okay
Answered by
3
Answer:
Step-by-step explanation:
Similar questions