Question

The given figure represents a circular lawn with a circular flower bed in the centre. The dimensions of the lawn are 18 m X 14 m and the diameter of the flower bed is 7 m. find the area of the lawn excluding the flower bed.

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Answer 1

Step-by-step explanation:

$dimensions \: of \: rectangular \: lawn= 18 m × 14 m \\ so \: area \: of \: rectangular \: lawn = l \times b = 18 \times 14 \: {m}^{2} \\ = 252 \: {m}^{2} \\ diameter \: of \: circular \: bed = \: 7 \: m \\ so \: radius \: of \: circular \: flower \: bed = \frac{diameter}{2} = \frac{7}{2} \: m \\ area \: of \: flower \: bed = \pi \: {r}^{2} = \frac{22}{7} \times {( \frac{7}{2}) }^{2} \\ = \frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} = \frac{77}{2} \: {m}^{2} \\ so \: area \: of \: lawn \: excluding \: circular \: flower \: bed \\ = 252 - \frac{77}{2} \\ = \frac{504 - 77}{2} \\ = \frac{427}{2} \: {m}^{2} \\ = 213.5 \: {m}^{2}$

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