Question

The given figure shows a ΔABC IN which AB=AC and BP=CQ Then,prove that
ΔAPQ is isosceles
​

Answer 1

Step-by-step explanation:

In triangle ABC,

AB = AC

Therefore, ∠B = ∠C

In triangles ABP and AQC,

AB = AC

∠B = ∠C

BP = QC

Thus,     ΔABP ≅ ΔAQC

By CPCT,

AP = AQ

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