The given figure shows a frield with the measurement given in metres .find the area of the field
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44
area of AED=20*37*1/2=370sq.m
area of DZC=1/2*10*25=125sq.m
area of AXB=1/2*30*12=180sq.m
area of BCZX=h(a+B)/2=15(25+30)/2=55(15)/2=825/2=412.5sq.m
total area of Field= ar(AED)+ar(DCZ)+ar(AXB)+ar(BCZX)=
=370+125+180+412.5
=1082.5sq.m
area of DZC=1/2*10*25=125sq.m
area of AXB=1/2*30*12=180sq.m
area of BCZX=h(a+B)/2=15(25+30)/2=55(15)/2=825/2=412.5sq.m
total area of Field= ar(AED)+ar(DCZ)+ar(AXB)+ar(BCZX)=
=370+125+180+412.5
=1082.5sq.m
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13
Area of quadrilateral ABCDE is 1615 square metres.
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