Question

The given figure shows a pentagon, inscribed in a [3]

Circle with centre O. Given AB = BC = CD and

∟ABC = 1320

.Calculate the value of

(i) ∟AEB (ii) ∟AED (iii) ∟COD.​

Answer 1

Answer:

COD please follow me please and I think its your answer

Answer 2

$\rm \underbrace \blue{Solution:}$

According to the question,

∵AB=BC=CD

& ∠BCD=132°

△AOB≅△BOC

BO=AO (radius)

BA=BC (given)

BO=CO (radius)

∴△AOB≅△BOC (by SSS rule)

so, ∠ABC=∠OBC

∠ABO= 132/2 =48°

48°+∠AOE=180°

(linear pair)

∠AOE=132°

In △AOE

132° +∠OAE+∠OEA+=180°

∠OEA=∠OAE (∵OA & OE are radius)

∠AEB=∠OAE=∠OEA= 48/2 =24°

∠AEB=∠OEA=24°

Also, △BOC≅△COD

⇒∠COD=48°